Carmichael number is not semiprime

From Number

Statement

Suppose is a composite natural number that is a Carmichael number, i.e., it is a Fermat pseudoprime to every base relatively prime to it. Equivalently, the universal exponent divides .

Then, is not a semiprime.

Facts used

  1. Carmichael number is square-free

Proof

We prove the contrapositive: a semiprime cannot be a Carmichael number.

By Fact (1), it suffices to restrict attention to a Carmichael number of the form where are distinct primes.

We have:

In particular, for to divide , we must have:

The first condition tells us that:

Since we already have , and since , this gives . In particular, this gives .

Similarly, the second condition tells us that . In particular, this gives .

Combining, we get , contradicting our requirement that be a product of distinct primes.