Carmichael number is not semiprime
Statement
Suppose is a composite natural number that is a Carmichael number, i.e., it is a Fermat pseudoprime to every base relatively prime to it. Equivalently, the universal exponent divides .
Then, is not a semiprime.
Facts used
Proof
We prove the contrapositive: a semiprime cannot be a Carmichael number.
By Fact (1), it suffices to restrict attention to a Carmichael number of the form where are distinct primes.
We have:
In particular, for to divide , we must have:
The first condition tells us that:
Since we already have , and since , this gives . In particular, this gives .
Similarly, the second condition tells us that . In particular, this gives .
Combining, we get , contradicting our requirement that be a product of distinct primes.